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May you please answer question #9

May you please answer question #9-example-1
User Motty
by
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1 Answer

7 votes

Answer: Approximately 0.78388 seconds

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Explanation:

Plug in t = 0 to find that

h = -16t^2 - 64t + 60

h = -16(0)^2 - 64(0) + 60

h = 60

The starting height is 60 feet.

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Now plug in h = 0 and solve for t.

h = -16t^2 - 64t + 60

0 = -16t^2 - 64t + 60

-16t^2 - 64t + 60 = 0

From here use the quadratic formula


t = (-b\pm√(b^2-4ac))/(2a)\\\\t = (-(-64)\pm√((-64)^2-4(-16)(60)))/(2(-16))\\\\t = (64\pm√(7936))/(-32)\\\\t = (64+√(7936))/(-32) \ \text{ or } \ t = (64-√(7936))/(-32)\\\\t \approx -4.78388 \ \text{ or } \ t \approx 0.78388 \\\\

We ignore the negative t value as a negative time doesn't make sense.

The only practical answer is roughly t = 0.78388 seconds.

User VBwhatnow
by
4.6k points