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Suppose PR = 54, solve for QR
4x-1
3x-1
P
R

Suppose PR = 54, solve for QR 4x-1 3x-1 P R-example-1
User Kgx
by
4.1k points

1 Answer

3 votes

Answer:


QR = 23

Explanation:

P, A, and R are collinear.

PR = 54


PQ = 4x - 1


QR = 3x - 1

To solve for the numerical length of PR, let's generate an equation to find the value of x.

According to the segment addition postulate:


PQ + QR = PR


(4x - 1) + (3x - 1) = 54 (substitution)

Solve for x


4x - 1 + 3x - 1 = 54

Combine like terms


4x + 3x - 1 - 1 = 54


7x - 2 = 54

Add 2 to both sides


7x - 2 + 2 = 54 + 2


7x = 56

Divide both sides by 7


(7x)/(7) = (56)/(7)


x = 8


QR = 3x - 1

Plug in the value of x into the equation


QR = 3(8) - 1 = 24 - 1


QR = 23

User Vuzun
by
3.9k points