Answer:
n(x+y)(x−y)
Explanation:
1. To factor this equation, first, you can see that both the x^2 and the y^2 have an n next to them. So, you can take out the n. You get this: n(x^2-y^2)
2. After you take the n out, you can also factor the (x^2-y^2) since they are both squared (to the second power). To do this, you simply split the two apart and make sure to include the negative. You get this, the final answer:
n(x+y)(x-y)
3. You can check it by multiplying out the answer, and once multiplied out, you get the original expression of x^2n-y^2n.
Hope this helped! Feel free to ask any questions :)