Answer:
It is a perfect cube with sides of 5.
Explanation:
If 125 was a perfect square, there would be a whole number A which, squared, would give us 125.
![A^2 = 125\\A = \pm 11.18...](https://img.qammunity.org/2021/formulas/mathematics/college/tndg10h0a40o8y8jiahxhoa1c6wwcft082.png)
We can see that the roots are not whole numbers.
(Tip: without a calculator, we can find this by testing
to see if any give us 125. We get 100, 121, 144 respectively. None of them is 125.)
If it was a perfect cube, there would be a whole number B which, cubed, would give us 125.
![B^3 = 125\\B = \sqrt[3]{125} \\B = 5](https://img.qammunity.org/2021/formulas/mathematics/college/kujo8zrdjzks9kbg30ofp657ak54l0d4w1.png)
As we can see, there IS a whole number B: 5 !
(Without a calculator, like the previous one, we could try
and we'd find that
= 125)
Answer: It is a perfect cube with sides of 5.