Question

0(-4,1), and Y (-2, 3).

Answer 1

Answer: If you trying to find the distance
`d=√(16)` or 4. If you trying to find midpoint its MP= (-3,2)

Step-by-step explanation:Distance formula
`d=\sqrt{(x_(2)-x_(1))^(2)+(y_(2)-y_(2))^(2) }`

`d=\sqrt{(-2-(-4))^(2)+(3-1})^(2) }` -2-(-4)=2 3-1=2

`d=\sqrt{2^(2)+2^(2) }` 2 squared is 4

`d=√(4+4)` equals
`d=√(16 )` or 4 simplyfied

Midpoint formula
`MP= ((x_(1)+x_(2) )/(2)), ((y_(1)+y_(2) )/(2) )`

`MP= ((-4+-2 )/(2)), ((1+3 )/(2) )` -4+-2=-6 1+3=4

`MP= ((-6)/(2) ), ((4 )/(2) )` -6/2= -3 4/2= 2

`MP= (-3,2)`