Question

3. A model rocket is launched straight upward at 58.8 m/s.

a. How long does it take for the rocket to reach its peak height?
b. what is the total time of flight of the model rocket ?
c. what is the peak height of the rocket from the ground ?

Answer 1

a). 6 seconds

b). 12 seconds

c). 176.4 meters

Step-by-step explanation:

a). Equation to be applied to calculate the time taken by the rocket to reach at the peak height,

v = u - gt

where v = final velocity

u = initial velocity = 58.8 m per sec

g = gravitational pull = 9.8 m per sec²

t = duration of the flight

At the peak height,

v = 0

Therefore, 0 = 58.8 - (9.8)(t)

t =
`(58.8)/(9.8)`

= 6 seconds

b). Total time of flight = 2(Time taken to go up)

= 2×6

= 12 sec

c). Formula to get the peak height is,

`h=ut-(1)/(2)gt^2`

h = (58.8)6 -
`(1)/(2)(9.8)(6)^2`

= 352.8 - 176.4

= 176.4 meters