Question

The expression (y^20) (y^-5)^2 is equivalent to y^n. What is the value of n? n = 27 n = 10 n = -200 n = 17

Answer 1

10.

Explanation:

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Answer 2

n = 10

Explanation:

Using the rules of exponents

`a^(m)` ×
`a^(n)` ⇔
`a^((m+n))`

`(a^(m)) ^(n)` =
`a^(mn)`

Given

(
`y^(20)` ) (
`(y^(-5)) ^(2)`

=
`y^(20)` ×
`y^(-10)`

=
`y^((20-10))`

=
`y^(10)` → in the form
`y^(n)` with n = 10