Question

A golf ball is hit with a club from the ground on a flat surface. The height of the ball, h(t), in feet, t seconds, after it was hit can be modeled by the function h(t)=40t-16t2

Answer 1

when the ball is hit as 0 second it has a height of 0 feet (because it hasnt done anything yet). The ball's height increases until it reaches its maximum height of 40 feet after 1.25 seconds (40t= 2.5/2). The balls height then decreases until it reaches 2.5 seconds after it was hit.

Answer 2

Explanation:

The question is incomplete. Find the complete question a=below;

A golf ball is hit with a club from the ground on a flat surface. The height of the ball, h(t), in feet, t seconds, after it was hit can be modeled by the function h(t)=40t-16t2. After how many seconds does the golf ball strike the ground?

The ball strikes the ground when the height h(t) = 0. To get the time wen the golf ball strikes the ground, we will substiute h = 0 into the modeled equation and calculate t as shown;

h(t)=40t-16t2

0 h(t)=40t-16t2

40t-16t² = 0

add 16t² to both side

40t-16t²+16t² = 0+16t²

40t = 16t²

40 = 16t

divide both sides by 16

t = 40/16.

t = 2.5secs

Hence the golf ball hit the ground after 2.5secs