Question

Can someone help with this

Answer 1

Draw a triangle then use pythagoras theorem

Answer 2

`GH=2√(10)`

Explanation:

Considering each is square is 1x1.

We have the points G(-2, -3) and H(0, 3).

Using the distance formula:

`$d=√((x_2 - x_1)^2 + (y_2 - y_1)^2)$`

`$d=√((-2 - 0)^2 + (-3 - 3)^2)$`

`$d=√((-2 )^2 + (-6)^2)$`

`$d=√(4 +36)$`

`d=√(40)=2√(10)`

Also, using the Pythagorean theorem:

`a^2+b^2=c^2`

`2^2+6^2=c^2`

`4+36=c^2`

`c=GH=√(40)=2√(10)`