Question

A cyclist accelerates from rest to 8 m/s in 3 seconds. How far did the cycles travel in 3 seconds?​

Answer 1

s(distance) =36m

Step-by-step explanation:

u(initial velocity) =0 m/s

a =8 m/s^2

t=3s

s=ut+1/2at^2

s=1/2(8)(3)^2

s=1/2(8)(3)(3)

s=4(9)

s=36m

Answer 2

`\boxed{\sf Distance \ travelled = 12 \ m}`

Given:

Initial speed (u) = 0 m/s (Accelerates from rest)

Final speed (v) = 8 m/s

Time taken (t) = 3 seconds

To Find:

Distance travelled by cyclist (s)

Step-by-step explanation:

From equation of motion of object moving with uniform acceleration in straight line we have:

`\boxed{ \bold{s = ((v + u)/(2) )t}}`

By substituting value of v, u & t in the equation we get:

`\sf \implies s = ( (8 + 0)/(2) ) * 3 \\ \\ \sf \implies s = (8)/(2) * 3 \\ \\ \sf \implies s = 4 * 3 \\ \\ \sf \implies s = 12 \: m`

`\therefore`

Distance travelled by cyclist (s) = 12 m