Question

Factor by grouping
ab + 7a + 4b + 28

Answer 1

`\boxed{ \bold{ \huge{ \boxed{ \sf{(b + 7)(a + 4)}}}}}`

Explanation:

`\sf{ab + 7a + 4b + 28}`

Take a common

`\dashrightarrow{ \sf{a(b + 7) + 4b + 28}}`

Take 4 common

`\dashrightarrow{ \sf{a(b + 7) + 4(b + 7)}}`

Take ( b + 7 ) common

`\dashrightarrow{ \sf{(b + 7)(a + 4)}}`

Hope I helped!

Best regards! :D

Answer 2

(b + 7)(a + 4)

Explanation:

ab + 7a + 4b + 28

separate the polynomial into 2 sections

(ab + 7a) (+ 4b + 28)

simplify each expression

a(b + 7)

4(b + 7)

you see that you have (b + 7) in both expressions. take that aside.

(b + 7)

you are left with a and positive 4. put these two together

(a + 4)

now put the expressions together

(b + 7)(a + 4)