Answer:
a. M = 50
b. M = 242
Explanation:
mean =
![(sum of scores)/(number of samples)](https://img.qammunity.org/2021/formulas/mathematics/college/6qgxjlog49nv3eb8hbqaje3z6sno1202tp.png)
⇒ sum of scores = mean x number of samples
Let the mean be represented by M, and the number of samples be represented by n,
sum of scores = M x n
a. When n = 5 for both samples,
The first sample's sum of scores = M x n
= 7.2 x 5
= 36
The second sample's sum of scores = M x n
= 12.8 x 5
= 64
The mean for the sum of scores of the combined set =
![(36 + 64)/(2)](https://img.qammunity.org/2021/formulas/mathematics/college/c97zpm9jbk7y7bktxofb9bs6udhau95emq.png)
= 50
When both samples have n = 5, the mean of the combined set is 50.
b. When the first sample has n = 5, the sum of scores = 36.
If n = 35 for the second sample, the sum of scores = M x n
= 12.8 x 35
= 448
The mean for the sum of scores of the combined set =
![(36 + 448)/(2)](https://img.qammunity.org/2021/formulas/mathematics/college/79b9ha0djk479awevlojmsi71zp8lmm7md.png)
= 242