Question

Ahh sorry! i need help again! question 25! if you can, please include steps! thanks!

Answer 1

In this question, we are required to find

`2 {x}^(2) - 3x {y}^(3)`

When, x = -2 and y = -1

We just need to plug the values of x and y in the given polynomial to get our required answer.

Given, Polynomial in variable x and y,

`2 {x}^(2) - 3x {y}^(3)`

Plugging values of x and y,

`2 {( - 2)}^(2) - 3( - 2)( - 1) {}^(3)`

According to PEMDAS, we need to do the exponents first, So let's simplify the exponents,

`2(4) - 3( - 2)( - 1)`

Opening the parantheses and finding the answer,

`2 * 4 - 3 * - 2 * - 1`

`8 -6`

`\boxed{ \red{2}}`

This is our required answer !!

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Answer 2

2

Explanation:

2x^2 -3xy^3

Let x=-2 and y =-1

2 ( -2)^2 -3 (-2) (-1)^3

Using PEMDAS, we do exponents first

2 ( 4) - 3(-2) (-1)

Multiply nexy

8 - 6

2