Answer:
![m_(water)=50.25g](https://img.qammunity.org/2021/formulas/chemistry/college/gf5kcf4jnutf9g7z59xpba3ju71tvsf8ed.png)
Step-by-step explanation:
Hello,
In this case, considering that the by-mass percent of water is:
![\% m/m=(m_(water))/(m_(sample))*100\%](https://img.qammunity.org/2021/formulas/chemistry/college/2l5wjprsqjx122d64ct9a5l4c9dxvpgwfj.png)
Given such percent and the mass of the sample, we can find the mass of water in grams in the sample by solving for it as shown below:
![m_(water)=(\%m/m*m_(sample))/(100\%)\\ \\m_(water)=(25\%*201g)/(100\%)\\ \\m_(water)=50.25g](https://img.qammunity.org/2021/formulas/chemistry/college/q5ryoo8cq47h5cn42vi0dssas5slq3iagl.png)
Best regards.