158k views
16 votes
N = 20

s = 18
H₀: σ² ≤ 384
H‎ₐ: σ₂ > 384

The null hypothesis is to be tested at the 5% level of significance. Give the critical value(s) from the table.
(no table is provided with the question)

A. 30.144
B. 31.410
C. 9.591 and 34.170
D. 8.907 and 32.852

User Anelson
by
5.9k points

1 Answer

6 votes

Answer:

A. 30.144

Explanation:

This is a Chi-Squared test

Given:


  • n=20

  • s=18

  • \textsf{H}_0:\sigma^2=384

  • \textsf{H}_1:\sigma^2 > 384
  • The significance level is 5%, so
    \alpha= 0.05

To use the Chi-Square distribution table, you need to know two values:

  • Degrees of freedom = (n - 1)
  • Significance level

Degrees of Freedom = n - 1 = 20 - 1 = 19

The significance level is 5%, so
\alpha= 0.05

This is a one-tailed test since
\textsf{H}_1:\sigma^2 > 384 so Upper tail area = 0.05

Reading from the table (attached), the critical value is: 30.144

(This means that we reject
\textsf{H}_0 if the test statistic is greater than 30.144)

N = 20 s = 18 H₀: σ² ≤ 384 H‎ₐ: σ₂ > 384 The null hypothesis is to be tested at-example-1
User Socialscientist
by
6.7k points