Answer:
a
![t = 3.33 \ ns](https://img.qammunity.org/2021/formulas/physics/college/txkmruq04xshhebowg1bfvphn4840b2rry.png)
b
i
![D_w =0.75 \ m](https://img.qammunity.org/2021/formulas/physics/college/ng988o4i9bv9j2m0vkiet2fhnoxyky32up.png)
ii
![D_g =0.67 \ m](https://img.qammunity.org/2021/formulas/physics/college/bqn54gjxh67i7ofzngv568xl59fkt7pwpj.png)
iii
![D_c =0.46 \ m](https://img.qammunity.org/2021/formulas/physics/college/jhjjfb6g2fr7tv2m097c2auo36uuhjn1sd.png)
Step-by-step explanation:
Generally the time taken to travel 1 m in a vacuum is mathematically represented as
![t = (1)/(c)](https://img.qammunity.org/2021/formulas/physics/college/5iptmcp6artcclshzw4l5jrfpyyyssiys8.png)
Here c is the speed of light with value
![c = 3.0*10^(8) \ m/s](https://img.qammunity.org/2021/formulas/chemistry/college/jwqbvh4csevamfq8jigmzd3ldsolrs0oou.png)
So
![t = (1)/(3.0*10^(8))](https://img.qammunity.org/2021/formulas/physics/college/o01dgjkbrhr69kr8xhiqf94ziao0qz1sle.png)
![t = 3.33*10^(-9) \ s](https://img.qammunity.org/2021/formulas/physics/college/1ffaqjgad2rty58z0wvw0son4ksrdeuckc.png)
![t = 3.33 \ ns](https://img.qammunity.org/2021/formulas/physics/college/txkmruq04xshhebowg1bfvphn4840b2rry.png)
The distance light travels in water is mathematically represented as
![D_w = (c)/(n_w) * t](https://img.qammunity.org/2021/formulas/physics/college/y4dr7d0r13gofrkj0kz82dod2zfczct1wk.png)
Here n_w is the refractive index of water with value 1.333
So
![D_w = (3.0*10^(8))/(1.333) * 3.33*10^(-9)](https://img.qammunity.org/2021/formulas/physics/college/xxh6jox3wuggl732emhbh1ysnnv3wnyqvr.png)
![D_w =0.75 \ m](https://img.qammunity.org/2021/formulas/physics/college/ng988o4i9bv9j2m0vkiet2fhnoxyky32up.png)
The distance light travels in glass is mathematically represented as
![D_g = (c)/(n_g) * t](https://img.qammunity.org/2021/formulas/physics/college/z8rtl4vy0zi4zdmocf4wt86o9tf4jgk8p6.png)
Here n_g is the refractive index of glass with value 1.5
So
![D_g = (3.0*10^(8))/(1.5) * 3.33*10^(-9)](https://img.qammunity.org/2021/formulas/physics/college/5v2qtlvwkj5i0em4ddfag3n5dl9vn5pso8.png)
![D_g =0.67 \ m](https://img.qammunity.org/2021/formulas/physics/college/bqn54gjxh67i7ofzngv568xl59fkt7pwpj.png)
The distance light travels in cubic zirconia is mathematically represented as
![D_c = (c)/(n_g) * t](https://img.qammunity.org/2021/formulas/physics/college/2chh9l5xtyg5qjsx3pcd9wqdlfz6ynr8w6.png)
Here n_c is the refractive index of cubic zirconia with value 2.15
So
![D_c = (3.0*10^(8))/(2.15) * 3.33*10^(-9)](https://img.qammunity.org/2021/formulas/physics/college/nypdommyhgcqxxab275b7n73dbu5ufoxfn.png)
![D_c =0.46 \ m](https://img.qammunity.org/2021/formulas/physics/college/jhjjfb6g2fr7tv2m097c2auo36uuhjn1sd.png)