Answer:
0.11 M
Step-by-step explanation:
The computation of molarity of the CH3COOH solution is shown below:-
![M_2 = (M_1V_1)/(V_2)](https://img.qammunity.org/2021/formulas/chemistry/high-school/nibbjk2hr3tdhxe96n0rv7u4u7kh36xnf6.png)
Where,
= Molarity of LioH = 0.0175
= Volume of LioH = 18.5 ml
= Volume of CH3COOH = 29.4 ml
Now, we will put the values into the formula
![= (0.0175* 18.5)/(29.4)\\\\ = (0.32375)/(29.4)](https://img.qammunity.org/2021/formulas/chemistry/high-school/asqvbsebqi4rdk7ivtqkmyx7r7v0n1xb3l.png)
Which gives result
= 0.011 M
Therefore for computing the molarity of the CH3COOH solution we simply applied the above formula.