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Write an equation of the line that passes through (18,2) and is parallel to the line 3y-x=-12 .

y =

1 Answer

8 votes

Answer:


y = (1)/(3)x-4

Explanation:

Step 1: Solve for y in the first equation


3y - x = -12


3y - x + x = -12 + x


(3y)/(3) = (x)/(3) - (12)/(3)


y = (1)/(3)x - 4

Step 2: Determine the important aspects

We know that our line is parallel to the other line that has a slope of 1/3 which means that our slope is also going to be 1/3. We also know that our line crosses the point (18, 2) which means that we can use the point slope form to determine our equation

Point Slope Form →
(y-y_1) = m(x - x_1)

Step 3: Plug in the information and solve


(y-2) = (1)/(3)(x - 18)


y - 2 = (1)/(3)x - 6


y - 2 + 2 = (1)/(3)x - 6 + 2


y = (1)/(3)x-4

Answer:
y = (1)/(3)x-4

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