Question

R=6,b=4,and g=9, (r+b-g)(b+g)=?

Answer 1

(r + b - g)(b + g) = 13

Explanation:

(r + b - g)(b + g)

• r = 6
• b =4
• g = 9

Substitute the numbers: (r + b - g)(b + g) ==> (6 + 4 - 9)(4 + 9)

Distribute (4 and 9):

4(6 + 4 - 9) + 9(6 + 4 - 9)

4(1) + 9(1)

4 + 9

Add:

4 + 9

13

Final answer: 13

Hope this helps!

Answer 2

`\qquad\qquad\huge\underline{{\sf Answer}}`

Let's evaluate ~

`\qquad \sf  \dashrightarrow \:(r + b - g)(b + g)`

Plug in the given values :

`\qquad \sf  \dashrightarrow \:(6 + 4 - 9)(4 + 9)`

`\qquad \sf  \dashrightarrow \:(1)(13)`

`\qquad \sf  \dashrightarrow \:13`

Hence, the equivalent value of given expression is 13