Question

Integral of dx/(e^x+e^-x)
given tanhu

Answer 1

= arctan( e^x)+c

Explanation:

∫1/e^x+e^-x × dx

Apply u - substitution

=∫1/u²+1 du

Use the common integral: =∫1/u²+1 du

= arctan(u)

Substitute back u =e^x

=arctan(e^x)

Add a constant to the solution

= arctan( e^x)+c