Question

Two point charges are on the x-axis. One charge, q1 = 10 nC, is located at the origin, and the othercharge, q2 = 18 nC, is located at x = 9.0 m. What is the force on q2?a) 20 nN in the positive x-directionb) 20 pN in the positive x-directionc) 20 nN in the negative x-directiond) 20 pN in the negative x-directione) 180 nN in the positive x-direction

Answer 1

The correct option is A

Step-by-step explanation:

Generally the force on
`q_2` is mathematically represented as

`F_2 = ( k * q_1 * q_2 )/( x^2)`

here k is the coulombs constant with value
`k = 9*10^(9)\ kg\cdot m^3\cdot s^(-4) \cdot A^(-2).`

=>
`F_2 = ( 9*10^(9) * 10*10^(-9) * 18*10^(-9) )/( 9^2)`

=>
`F_2 = 2*10^(-8) \ N`

=>
`F_2 = 20*10^(-9) \ N`

=>
`F_2 = 20nN`

The direction is in the positive x-axis because both charge are of the same polarity so the will repel hence
`q_2` will move toward the positive x-axis