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What is the molality of a solution made by dissolving 3.71 g of sodium chloride in 0.535 L of water?

User BowPark
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Answer:

Molality of the solution is 0.119 mol/kg

Step-by-step explanation:

Molality is the type of concentration that indicates the moles of solute in 1 kg of solvent.

As we assume water's density as 1 g/mL, we need to calculate the mass of water (our solvent).

We convert 0.535 L to mL → 0.535 L = 535 mL

By the way, water's mass is 535 g.

We convert the mass from g to kg → 535 g = 0.535kg

We need to calculate the moles of solute, NaCl.

3.71 g . 1mol / 58.45 g = 0.0635 mol

Molality = mol/kg → 0.0635 mol / 0.535kg = 0.119 m

User Maralla
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