Question

How many gallons of a 90​% antifreeze solution must be mixed with 80 gallons of 25​% antifreeze to get a mixture that is 80​% ​antifreeze?

Answer 1

x=440 gaL 90 % Antifreeze II

Step-by-step explanation:

In the problem, there are two types of antifreeze

antifreeeze I and

antifreeze II

antifreeze I 25 ----80 gal

Antifreeze II 90 ----- x gal

Total 80 ---------------- (80 + x ) gal

(25*80)+(90*x)=80(80+x)

2000+90x=6400+80x

90x-80x=6400-2000

10x=4400

divide both sides by 10 we have

x= 440

x=440 gaL 90 % Antifreeze II