Question

Bailey was driving down the street on her motorcycle and reduced her velocity from 25

m/s to 15 m/s over a distance of 8 meters. What is the magnitude of the motorcycle's
acceleration during this time!

Answer 1

a = - 25 m/s²

Step-by-step explanation:

The magnitude of acceleration or deceleration of an object can be found by using the third equation of motion as follows:

2as = Vf² - Vi²

where,

a = magnitude of acceleration = ?

Vf = Final Velocity = 15 m/s

Vi = Initial Velocity = 25 m/s

s = distance traveled = 8 m

Therefore,

2a(8 m) = (15 m/s)² - (25 m/s)²

a = (- 400 m²/s²)/(16 m)

a = - 25 m/s²

Here negative sign indicates deceleration