Question

Solve for y 2x+y-3z=5

Answer 1

Option A

Explanation:

Since the "y" variable is inside a root, we need to square both sides of the equation to open the root and solve for y.

When squaring both sides, we get;

`\implies √(2x + y - 3z) = 5`

`\implies(√(2x + y - 3z))^(2) = 5^(2)`

`\implies2x + y - 3z = 25`

Now, simply isolate the y-variable to determine its value. This can be done by subtracting 2x on both sides of the equation.

`\implies2x + y - 3z = 25`

`\implies2x + y - 3z - 2x = 25 - 2x`

`\implies y - 3z = 25 - 2x`

Now, add 3z both sides of the equation to further isolate the y-variable.

`\implies y - 3z + 3z = 25 - 2x + 3z`

`\implies y = 25 - 2x + 3z`

Therefore, Option A is correct.

Answer 2

A. y=-2x+3z+25

Explanation:

Isolate the term of x and y from one side of the equation.

To solve:

• The value of y.

`\Longrightarrow: \sf{√(2x+y-3z)=5}`

2x+y-3z=25

First, you have to subtract by 2x-3z from both sides.

`\Longrightarrow: \sf{2x+y-3z-\left(2x-3z\right)=25-\left(2x-3z\right)}}`

Solve.

`\Longrightarrow: \boxed{\sf{y=25-2x+3z}}}`

• Therefore, the correct answer is "A. y=-2x+3z+25".

I hope this helps, let me know if you have any questions.