Question

The sum of 7 consecutive odd integers is 217. What is the smallest of the integers?

Answer 1

25

Explanation:

Let the smallest odd integer be n.

The integers are: n, n + 2, n + 4, n + 6, n + 8, n + 10, n + 12

Their sum is 217.

n + n + 2 + n + 4 + n + 6 + n + 8 + n + 10 + n + 12 = 217

7n + 42 = 217

7n = 175

n = 25

Answer: 25

Answer 2

25

Explanation:

n+(n+2)+(n+4)+(n+6)+(n+8)+(n+10)+(n+12)=217

7n+42=217

7n=175

n=25

25+27+29+31+33+35+37=217