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Ej bisects def, m dej-5x+7, m JEF=8x-8. find x

1 Answer

1 vote

Answer:

x = 5

Explanation:

The information given has been sketched out in the attachment below.

Line segment EJ is an angle bisector of angle DEF. Therefore, m<DEJ = m<JEF.

The equation to find x would be expressed as follows:

5x + 7 = 8x - 8

Subtract 5x from each side (subtraction property of equality)

5x + 7 - 5x = 8x - 8 - 5x

5x - 5x + 7 = 8x - 5x - 8

0 + 7 = 3x - 8

7 = 3x - 8

Add 8 to both sides of the equation (addition property of equality)

7 + 8 = 3x - 8 + 8

15 = 3x

Divide both sides by 3

15/3 = 3x/3

5 = x

x = 5

Ej bisects def, m dej-5x+7, m JEF=8x-8. find x-example-1
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