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What is the temperature of 1.485 moles of N₂ gas at a pressure of 1.072 atm and a volume of 20 L?
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What is the temperature of 1.485 moles of N₂ gas at a pressure of 1.072 atm and a volume of 20 L?

User Rmflow
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1 Answer

5 votes

Answer:

178.67K

Step-by-step explanation:

PV=nRT

T=PV/nR

= 1.072atm*20L/1.485mol*0.0821LatmK^-1

=178.67K

User Michael Wehner
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5.1k points
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