Question

Locate the vertex and the axis of symmetry of the quadratic graph y = 7 * (x - 4) ^ 2 - 5 . Determine the range.

Answer 1

vertex is (4, -5)

Explanation:

given:

y = 7 * (x - 4) ^ 2 - 5

find:

Determine the range.

y = 7 * (x - 4) ^ 2 - 5

rewrite in the form of y = ax² + bx + c

y = 7x² - 56x + 107

the parameters are:

a = 7

b = -56

c = 107

Xv = - ( - 56 )

2 * 7

simplify:

Xv = 4

plugin values into Yv

Yv = -5

therefore the vertex is (4, -5)

Answer 2

The vertex is (4,-5) and the axis of symmetry is x = 4. The range is all real numbers

Explanation:

vertex is calculated by -b/2a so the vertex would be -5/2(2) which is equal to (4,-5).

The axis of symmetry is the x number in the vertex so it would be x = 4.