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A compound contains 70.0 or iron and 30.1 oxygen what is its empirical formula

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Answer:

The empirical formula would be Fe2o3

Step-by-step explanation:

you first take the grams or the percent of each element, then transform them from grams to moles.

After getting the number of mols you want to divide each mol by the lowest number of mol.

EX) for this problem the number of moles of Fe(iron) would be 1.253 mol and the moles for the oxygen would be 1.881 mol... so you take the lowest, 1.253, and divide both to get what's called a mol fraction.

1.253/ 1.253 =1Fe

1.881/ 1.253= 1.5

now we want a whole number since we're finding the formula of a compound... and since there is a 1.5 you would multiple that by 2 giving you 3 for oxygen and giving you 2 for iron.

then these whole numbers will give you the subscripts that's needed for your empirical formula :)

- Hope this helps!!!

User Abhishek Pathak
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