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y = c1 cos(3x) + c2 sin(3x) is a two-parameter family of solutions of the second-order DE y'' + 9y = 0. If possible, find a solution of the differential equation that satisfies the given side conditions. The conditions specified at two different points are called boundary conditions. (If not possible, enter IMPOSSIBLE.)

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Complete Question

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Answer:

The value is
y  =  5sin3x

Explanation:

From the question we are told that


y =  c_1\ cos3x + c_2 \  sin 3x

given that y(0) = 0

We have that


c_1\ cos3(0) + c_2 \  sin 3(0)  =  0

=>
c_1 =  0

This means that


y  =  c_2 \  sin 3x

We also given that


y[(\pi)/(6) ] =  5

So


c_2  sin (3 *  (\pi)/(6) )  =  5

=>
c_2  =  5

Hence


y  =  5sin3x

y = c1 cos(3x) + c2 sin(3x) is a two-parameter family of solutions of the second-order-example-1
User Amogh Talpallikar
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