Question

The radius of a uranium atom is 149 pm. How many uranium atoms would have to be laid side by side to span a distance of 1.66 mm?

Answer 1

Given :

Radius of uranium atom ,
`R=149\ pm = 149* 10^(-12)\ m` .

To Find :

How many uranium atoms would have to be laid side by side to span a distance of 1.66 mm .

Solution :

Diameter of uranium atom :

`D=2r=2* 149* 10^(-12)\ m\\\\D=298* 10^(-12)\ m`

Number of atoms are :

`n=(D)/(d)\\\\n=(1.66* 10^(-3)\ m)/( 298* 10^(-12)\ m)\\\\n=5.57* 10^(6)`

Hence , this is the required solution .