Question

Which value is equivalent to 7 x 5 x 2 divided by 7 x 3 to the 2nd power x 5 to the 0 power divided by 2 to the negative 3rd power x 2 to the negative 9 power

Answer 1

This is hard to read, but i guess that the equation is:

`7*5*2/7*3^2*5^0/2^(-3)*2^(-9)`

So we have some things to solve:

First, for any number:

x^0 = 1

then 5^0 = 1.

And for negative powers,

x^-n = (1/x)^n.

And we

Then we can rewrite our equation as:

`(7*5*2*3^2*1*2^3)/(7*2^9)`

now we can cancel the seven in the numerator and the denominator

`(5*2*3*2^3)/(2^9)`

now, remember the relation:

a^x*a^y = a^(x+y)

then:

2*2^3 = 2^4

and 2^4/2^9 = 2^-5 = (1^2)^5

Then our equation is:

`(5*3)/(2^5)`

15/2^5 = 0.46875