Question

There are three consecutive integers with a sum of 39. which integers are they?​

Answer 1

The three integers are 11, 13, and 15 .

Explanation:

We shall consider the integers as x, ( x + 2 ) , and ( x + 4 ) . The sum of these is 39, so we can write:

x + (x + 2) + (x + 4) = 39

Open the brackets and simplify.

x + x + 2 + x + 4 = 39

3x + 6 = 39

Subtract 6 from each side.

3x = 33

Divide both sides by 3.

x=11

Therefore: (x + 2) = 13 and (x + 4) = 15

Answer 2

The three integers are

11, 13, and 15.

Explanation:

We shall consider the integers as

x, (x+2), and (x+4). The sum of these is 39, so we can write:

x+(x+2)+(x+4)=39

Open the brackets and simplify.

x+x+2+x+4=39 3x+6=39 Subtract 6 from each side.3x=33 Divide both sides by 3.x=11 Therefore: (x+2)=13and (x+4)=15