Question

A sample of helium gas has a volume of 1.25 L and a temperature of 22 °C, under a constant pressure. What is the new volume if the temperature is increased to 45 °C?

Answer 1

the new volume is 1.35L

Step-by-step explanation:

The computation of the new volume in the case when the temperature rises to 45 degrees is shown below:

GIven that

Volume = 1.25L

And, the temperature is 22 degrees celsius

So,
`T_1` = (275 + 22)k

= 297 k

Now

`T_2` = (275 + 45)k

= 320 k

Now as it is a constant pressure

So, the new volume is

`(V_1)/(T_1) = (V_2)/(T_2) \\\\V_2 = (V_1)/(T_1)* T_2 \\\\= (1.25)/(297)* 320`

= 1.35L

hence, the new volume is 1.35L