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A student bikes 5.00 km East to school in 30.0 min, realizes he forgot his calculator for physics, spends 30.0 min going back going home, and then races back to school in 27.0 minutes.

1.What is the students total distance traveled ?
2. Determine the students average speed ?
3. What is the students total displacement ?
4. Determine the students average velocity ?

User Radven
by
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1 Answer

4 votes

Step-by-step explanation:

Given data

distance = 5km

time taken to travel to school= 30 min

1. the total distance traveled is

from home to school+ school to home+ home back to school

5km+5km+5km= 15 km

2. Determine the students average speed

average speed is the total distance divided by the total time taken

= (5+5+5)/(30+30+27)

= 15/87 km/min

3 What is the student total displacement

the displacement tells how far a place is hence the displacement is 5km (i.e the school is 5km from his home)

4. Determine the students average velocity

a. speed home to school

v= 5/30= 0.166 km/min

b. school back home

v= 5/30= 0.166 km/min

c. speed home to school

v= 5/27= 0.185 km/min

Average velocity = (0.185 + 0.166 + 0.166)/3= 0.517/3= 0.17 km/min

User Jammur
by
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