Answer:
![(√(30))/(5), -(√(30))/(5)](https://img.qammunity.org/2021/formulas/mathematics/college/4vpxmpooqltdpfn1595dmu2m3pfbgvtjtv.png)
Explanation:
We have the equation
![-5x^2 + 6 = 0](https://img.qammunity.org/2021/formulas/mathematics/college/3t97ko5trcsphm3ahb4cvjs5xqquu53u1f.png)
Since we know that any number multiplied by 0 is 0, we can safely make the term
to add to this.
So our equation now is
![-5x^2 + 0x + 6](https://img.qammunity.org/2021/formulas/mathematics/college/u5q5l4pk7amq8bliir6lpusal50xa52ctx.png)
We can now solve for this using the quadratic formula, which is
.
b is the coefficient on the x term, a is the coefficient on the
term, and c is the constant.
Let's substitute inside the equation, since we know
,
and
.
![\frac{{ - 0 \pm \sqrt {0^2 - 4\cdot-5\cdot6} }}{{2\cdot-5}}}\\\\\frac{{ 0 \pm \sqrt {0 -( -120)} }}{{-10}}}\\\\\frac{{ 0 \pm \sqrt {120} }}{{-10}}}\\\\\frac{{\pm \sqrt {120} }}{{-10}}}\\\\](https://img.qammunity.org/2021/formulas/mathematics/college/zz03xqby0l7z3xrd75akko29r1dezqe993.png)
![(√(30))/(5), -(√(30))/(5)](https://img.qammunity.org/2021/formulas/mathematics/college/4vpxmpooqltdpfn1595dmu2m3pfbgvtjtv.png)
Hope this helped!