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Find the sum of the following geometric sequences. d) 3 terms a= 16 r=3/4​

User Fried Rice
by
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1 Answer

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Answer:

S₃ = 37

Explanation:

given a₁ = 16 and r =
(3)/(4) , then

a₂ = a₁ ×
(3)/(4) = 16 ×
(3)/(4) = 12

a₃ = a₂ ×
(3)/(4) = 12 ×
(3)/(4) = 9

then

S₃ = a₁ + a₂ + a₃ = 16 + 12 + 9 = 37

User Smukamuka
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