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Mary drove 4 hours to reach her camping spot. She increased her speed by 15 miles per hour reducing her travel time by one hour. How fast did she drive going to the camping spot?

User Yaoxing
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1 Answer

3 votes

Answer:

45 miles per hour

Explanation:

Mary drove 4 hours to reach her camping spot. Driving home, she increased her speed by 15 miles per hour, reducing her travel time by 1 hour. How fast did she drive going to the camping spot?

d = rt

Where,

d = distance

r = rate of speed

t = time

Going to the camping spot

d=rt

Where, t = 4 hours

d = r × 4

d = 4r (1)

Driving home

She reduced her travel time by 1 hour

That is t = 4 -1 = 3 hours

Then increased speed by 15 miles per hour

That is r = r + 15

d=rt

d = (r+15) × 3

d = 3r + 45 (2)

Equating the two equations

4r = 3r + 45

Collecting like terms

4r - 3r = 45

r = 45

r = 45 miles per hour

check:

d = 4r

d = 45*4

=180 miles

d = 3r + 45

d = 3*45 + 45

= 135 + 45

=180 miles

User Bharat Chodvadiya
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5.9k points