Answer:
![y = 3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/acoo9469po7wyuqrdt46fqzahwmx3ebgvr.png)
Explanation:
Given
Trip = 250 miles
Speed for first x hours = 60 miles/hour
Speed for next y hours = 50 miles/hour
x = 1
Required
Find y
To solve this question, we'll make use of:
![Distance = Speed * Time](https://img.qammunity.org/2021/formulas/mathematics/high-school/wxewtog1tl71s8wo39jhxpvy6b00cxv0qs.png)
For x hours:
![Distance = 60miles/hour * x](https://img.qammunity.org/2021/formulas/mathematics/high-school/kpjjoe4dtgj9pvjvsdebvyjp1i6unyr2n4.png)
Substitute 1 hour for x
![Distance = 60\ miles/hour * 1\hour](https://img.qammunity.org/2021/formulas/mathematics/high-school/qgjktqclpho61gxzuz1chrpv05idvewsv3.png)
![Distance = 60\ mile](https://img.qammunity.org/2021/formulas/mathematics/high-school/1owfkkzmzlpqjqgbyz257yx23y98rigd2q.png)
For y hours:
![Distance = 50\ miles/hour * y\ hours](https://img.qammunity.org/2021/formulas/mathematics/high-school/2ev4l78j02i7k9ef3i2yvwefdcy25rfgtp.png)
![Distance = 50y\ miles](https://img.qammunity.org/2021/formulas/mathematics/high-school/gadmfklgsql4w3ashkgs1s5gb4i23cii7w.png)
Given that total distance is 210 miles;
We have that:
![Total Distance = 60\ miles + 50y\ miles](https://img.qammunity.org/2021/formulas/mathematics/high-school/n94lzmo1ym1281j1lqwaotygedqnd8m6h0.png)
![210\ miles = 60\ miles + 50y\ miles](https://img.qammunity.org/2021/formulas/mathematics/high-school/7rzvkh0y097au1unhhi96ynd4ff82qct5g.png)
Solve for y
![210 - 60 = 50y](https://img.qammunity.org/2021/formulas/mathematics/high-school/j64p4l4beyst0cn5iaed6ywgh7fydurdv3.png)
![150 = 50y](https://img.qammunity.org/2021/formulas/mathematics/high-school/3a7hxpwgf6hhqbr5cixhra0vgjaaefktmr.png)
![y = (150)/(50)](https://img.qammunity.org/2021/formulas/mathematics/high-school/av5lhckctpibsjx02p0097hscwttjaxrbh.png)
![y = 3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/acoo9469po7wyuqrdt46fqzahwmx3ebgvr.png)
Hence,
y = 3 hours