Answer:
The sequence has common difference 3, and its general nth term can be written as:

Explanation:
In order to define the sequence, we recall the formula for the nth term of an arithmetic sequence as:

where "d" is the common difference for the sequence (our unknown in this case), and the nth term is our fourth term (n = 4) which equals 11, and the first term is 2:

Therefore our sequence has common difference 3, and its general nth term can be written as:
