Question

60

and that angle 8 terminates in quadrant III, then what is
Given that sina
the value of cos 0?

Answer 1

sin = y / r

sin = -60 / 61

y = -60

r = 61

x = ?

---To find x, we'll use the Pythagorean theorem.

60^2 + x^2 = 61^2

3600 + x^2 = 3721

x^2 = 121

x = 11

Quadrant 3 is (-, -) = x and y coordinates are both negative.

Therefore, x = -11.

cos = x / r

x = -11

r = 61

cos = -11 / 61

Hope this helps!