Answer:
B. 7.1
Explanation:
Given the sample data 2 6 15 9 11 22 1 4 8 19, before we can get the standard deviation, we need to first calculate the mean.
mean = 2 +6 +15 +9 +11 +22 +1 +4 +8 +19/10
mean = 97/10
mean = 9.7
Standard deviation for ungrouped data is expressed using the formula;



Hence the standard deviation of the sample data is 7.1