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Evaluate the following integral. e^x+3/e^x g

User BaldyHDL
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1 Answer

6 votes

Answer:


x -3e^(-x) + C

Explanation:

Given the integral
\int\limits {(e^(x)+3)/(e^x) } \, dx, we are to evaluate it. Note that sum of integral is equal to the integral of its individual sum as shown;


\int\limits {(e^(x)+3)/(e^x) } \, dx = \int\limits {(e^(x))/(e^x) } \, dx + \int\limits {(3)/(e^x) } \, dx


= \int\limits 1\, dx + 3\int\limits {e^(-x) \, dx \\\\


= x + 3(-e^(-x))\\\\= x -3e^(-x) + C

Hence the value of the evaluated integral is
x -3e^(-x) + C where C is the constant of integration.

User Mike Katz
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