Question

Determine the number of water molecules in 115g of chromium(III) oxalate trihydrate.

Answer 1

`4.92x10^(23)molecules H_2O`

Step-by-step explanation:

Hello,

In this case, since the chromium(III) oxalate trihydrate is Cr₂(C₂O₄)₃ ·3H₂O whose molar mass is 422 g/mol and one mole of chromium(III) oxalate trihydrate contains three moles of water, by also considering that one mole of substance contains the Avogadro´s number in particles, the number of water molecules turns out:

`=115gCr_2(C_2O_4)_3\ 3H_2O*(1molCr_2(C_2O_4)_3\ 3H_2O)/(422gCr_2(C_2O_4)_3\ 3H_2O)*(3molH_2O)/(1molCr_2(C_2O_4)_3\ 3H_2O) *(6.022x10^(23)molecules H_2O)/(1molH_2O) \\\\=4.92x10^(23)molecules H_2O`

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