Question

A runner has an original velocity of 6 m/s and slows to a final velocity of 0 m/s. If the runner covers a

displacement of 12 m while slowing down, how long time) did it take the runner to stop?

Answer 1

4 s

Step-by-step explanation:

Given:

Δx = 12 m

v₀ = 6 m/s

v = 0 m/s

Find: t

Δx = ½ (v + v₀) t

12 m = ½ (0 m/s + 6 m/s) t

t = 4 s