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Bryan Allen pedaled a human-powered aircraft across the English channel from the cliffs of Dover to Cap Gris-Nez on June 12, 1979. He flew for 169 minutes at an average velocity of 3.53 m/s in a direction 45.0∘ degrees south of east. Allen encountered a headwind averaging 2.00 m/s almost precisely in the opposite direction of his motion relative to the earth. What was his average velocity relative to the air?

User Kbrown
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1 Answer

1 vote

Answer:

The answer is "
5.53 \ (m)/(s)"

Step-by-step explanation:

apply the formula for calculating the average velocity to the relative air


V_(PG) =V_(PA)+V_(AG)


\Rightarrow V_(PA) = V_(PG) -V_(AG)

Given value:


V_(AG) = -2 \ (m)/(s)


V_(PG) =3.53


\Rightarrow V_(PA) = 3.53 - (-2) \\\\\Rightarrow V_(PA) = 3.53 +2 \\\\\Rightarrow V_(PA) = 5.53 \\\\

The final answer is "
5.53 \ (m)/(s)" in the south-east direction.

User Kathir Subramaniam
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