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Draw the products formed when 2−propanol [(CH3)2CHOH], the main ingredient of rubbing alcohol, is treated with H2SO4.

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Answer:

Step-by-step explanation:

Elimination reaction occurs when 2−propanol [(CH3)2CHOH] is treated with H2SO4, this is because the H2SO4 is a dehydrating agent. With concentrated tetraoxosulphate (VI) acid at 180°C, 2 - propanol reacts to form a conjugate acid and a conjugate base.

The reaction formation and the products can be seen in the attached image below.

Draw the products formed when 2−propanol [(CH3)2CHOH], the main ingredient of rubbing-example-1
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