Question

At which point in time does an object with the motion represented in the graph have an

instantaneous acceleration of -2 m/s^2?

Answer 1

4s.

Step-by-step explanation:

Hello,

In this case, considering that the instantaneous acceleration is computed via the change in the velocity divided by the change in the time, at 4 s we can evidence that the instantaneous acceleration is -2m/s² since the initial velocity at t=0s is 8m/s and at t=4s the velocity is 0 m/s, meaning that such decrease accounts for a deceleration process which is represented by a negative acceleration, and the value is:

`a=(0m/s-8m/s)/(4s-0s)\\ \\a=-2m/s^2`

Best regards.