Question

If 5x+3y=41 and x+y=11, then the value y-x is​

Answer 1

Answer:y-x=3

Step-by-step explanation: substitution method

5x+3y=41........ equation 1

x+y=11 .........equation 2

Since we are given two different equations in terms of two different linear equations, let us try to solve them using the concept of method of substitution:

we find that y=11-x

we will substitue y into equation 1

5x+3(11-x) = 41

5x+33-3x=41

5x-3x=41-33

2x=8

2x/2=8/2

x=4

x+y=11

then you substitute

4+y=11

y=11-4

y=7

y-x

7-4=3

Answer 2

`y-x=3`

Explanation:

Subtract y from both sides of the equation.

`x = 11-y`

`5x+3y=41`

Replace all occurrences of x in
`5x+3y=41` with 11 -y

`x=11-y`

`5(11-y)+3y=41`

simplify
`5(11-y)+3y=41`

`x=11-y`

`55-5y+3y=41`

add -5y and 3y

`x= 11-y`

`55- 2y=41`

Solve for y in the second equation.

Move all terms not containing y to the right side of the equation.

`x=11-y`

`-2y=-14`

Divide each term by − 2 and simplify.

`x=11-y`

`y=7`

Replace all occurrences of y in x

`x=11-(7)`

`y=7`

simplify.

`x=4`

`y=7`

Replace the variable x with 4 in the expression.

`y-(4)`

Replace the variable y with 7 in the expression.

`(7) - (4)`

Multiply − 1 by 4 .

`7-4`

Subtract 4 from 7 .

`3`